This is supposed to be 5th grade?

Anna's farm picked a total of 310 pumpkins. Anna separated the pumpkins into small and large. She sold the small pumpkins for $3 each and the large ones for $9 each. She sold all of the pumpkins for total sales of $1,950. How many small and large pumpkins did Anna originally pick?

s + l = 310

3s + 9l = 1950

s = -l + 310

3(-l + 310) + 9l = 1950

-3l + 930 + 9l = 1950

6l = 1020

l = 170

s = -170 + 310

s = 140

She had 140 small ones and 170 large ones

Check:

140 + 170 = 310 and 3(140) + 9(170) = 1950

310 = 310 and 420 + 1530 = 1950

1950 = 1950

I hope this helps.

Let the numbers of small and large pumpkins be a and b. Then

a + b = 310

3a + 9b = 1 950

Multiply the 1st equation by 3 and subtract it from the 2nd

3a + 9b = 1 950

-(3a + 3b = 930)

6b = 1 020

b = 170

Now use the 1st equation again.

a = 310 – b = 310 – 170 = 140

So she had 140 small pumpkins and 170 large ones.

Happy Halloween!

5th grade?? This is more like 8th grade.

In one variable (x= small pks) and 310-x= large pks.

Then SUM(costxnumber sold)=total sales

or

3x + 9(310-x) = 1950 etc…..

U will be requiring statements

let the small pimpkins be x

let the big pimpkins be y

Total = x + y

310 = x + y or x + y = 310

small was sold @ 3 and big @9

It was sold for 1950

so 3x + 9y = 1950

*—————————————————-

*method 1

*—————————————————-

3x+9y = 1950

x+ y = 310 Multiplying by 3 we get 3x+3y=930

so

3x +9y = 1950

3x +3y = 930 By subtracting we get

——————–

6y = 1020 so y = 170

substituting in the 1st equation we get

x+170 = 310

x= 310-170

x= 140

*———————————————————–

*Method 2

*———————————————————–

x+y =310

x=(310-y)

substituting in second Equation

3x+9y = 1950

3(310-y)+9y =1950

930 -3y + 9y = 1950

930 + 6y = 1950

6y = 1950 -930

6y =1020

y = 170

substituting in the 1st equation we get x = 140