A. F/M2

B. F/ M1

C. F/M1 + M2

D. 2F/M1+M2

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The masses can be considered as a single mass, since they are connected. (The length of the cord can be arbitrarily short — so short that the masses are effectively one.)

So the mass being a

is M₁ + M₂. F = Ma, so a = F/M = F/(M₁ + M₂).

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By Newton's Second Law, F = (M₁ + M₂)*a

and so the acceleration is a = F/(M₁ + M₂) ◄ C closest

option C written this way : a = F/(m1+m2) …(parentheses do matter)